Integrand size = 41, antiderivative size = 129 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=\frac {i a^3 B x}{c^3}+\frac {a^3 B \log (\cos (e+f x))}{c^3 f}-\frac {a^3 (i A+B) (1+i \tan (e+f x))^3}{6 c^3 f (1-i \tan (e+f x))^3}-\frac {2 a^3 B}{c^3 f (i+\tan (e+f x))^2}-\frac {4 i a^3 B}{c^3 f (i+\tan (e+f x))} \]
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Time = 0.19 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.073, Rules used = {3669, 79, 45} \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=-\frac {a^3 (B+i A) (1+i \tan (e+f x))^3}{6 c^3 f (1-i \tan (e+f x))^3}-\frac {4 i a^3 B}{c^3 f (\tan (e+f x)+i)}-\frac {2 a^3 B}{c^3 f (\tan (e+f x)+i)^2}+\frac {a^3 B \log (\cos (e+f x))}{c^3 f}+\frac {i a^3 B x}{c^3} \]
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Rule 45
Rule 79
Rule 3669
Rubi steps \begin{align*} \text {integral}& = \frac {(a c) \text {Subst}\left (\int \frac {(a+i a x)^2 (A+B x)}{(c-i c x)^4} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {a^3 (i A+B) (1+i \tan (e+f x))^3}{6 c^3 f (1-i \tan (e+f x))^3}+\frac {(i a B) \text {Subst}\left (\int \frac {(a+i a x)^2}{(c-i c x)^3} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {a^3 (i A+B) (1+i \tan (e+f x))^3}{6 c^3 f (1-i \tan (e+f x))^3}+\frac {(i a B) \text {Subst}\left (\int \left (-\frac {4 i a^2}{c^3 (i+x)^3}+\frac {4 a^2}{c^3 (i+x)^2}+\frac {i a^2}{c^3 (i+x)}\right ) \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {i a^3 B x}{c^3}+\frac {a^3 B \log (\cos (e+f x))}{c^3 f}-\frac {a^3 (i A+B) (1+i \tan (e+f x))^3}{6 c^3 f (1-i \tan (e+f x))^3}-\frac {2 a^3 B}{c^3 f (i+\tan (e+f x))^2}-\frac {4 i a^3 B}{c^3 f (i+\tan (e+f x))} \\ \end{align*}
Time = 4.96 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.57 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=-\frac {a^3 \left (3 B \log (i+\tan (e+f x))+\frac {A-7 i B-18 B \tan (e+f x)-3 (A-5 i B) \tan ^2(e+f x)}{(i+\tan (e+f x))^3}\right )}{3 c^3 f} \]
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Time = 0.22 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.96
method | result | size |
risch | \(-\frac {{\mathrm e}^{6 i \left (f x +e \right )} a^{3} B}{6 c^{3} f}-\frac {i {\mathrm e}^{6 i \left (f x +e \right )} a^{3} A}{6 c^{3} f}+\frac {B \,a^{3} {\mathrm e}^{4 i \left (f x +e \right )}}{2 c^{3} f}-\frac {B \,a^{3} {\mathrm e}^{2 i \left (f x +e \right )}}{c^{3} f}-\frac {2 i B \,a^{3} e}{c^{3} f}+\frac {B \,a^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )}{c^{3} f}\) | \(124\) |
derivativedivides | \(\frac {4 i a^{3} B}{3 f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{3}}-\frac {4 a^{3} A}{3 f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{3}}-\frac {2 i a^{3} A}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{2}}-\frac {4 a^{3} B}{c^{3} f \left (i+\tan \left (f x +e \right )\right )^{2}}-\frac {5 i a^{3} B}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )}+\frac {a^{3} A}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )}-\frac {a^{3} B \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f \,c^{3}}+\frac {i a^{3} B \arctan \left (\tan \left (f x +e \right )\right )}{f \,c^{3}}\) | \(185\) |
default | \(\frac {4 i a^{3} B}{3 f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{3}}-\frac {4 a^{3} A}{3 f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{3}}-\frac {2 i a^{3} A}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )^{2}}-\frac {4 a^{3} B}{c^{3} f \left (i+\tan \left (f x +e \right )\right )^{2}}-\frac {5 i a^{3} B}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )}+\frac {a^{3} A}{f \,c^{3} \left (i+\tan \left (f x +e \right )\right )}-\frac {a^{3} B \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f \,c^{3}}+\frac {i a^{3} B \arctan \left (\tan \left (f x +e \right )\right )}{f \,c^{3}}\) | \(185\) |
norman | \(\frac {\frac {\left (-i B \,a^{3}+a^{3} A \right ) \tan \left (f x +e \right )}{c f}+\frac {\left (-5 i B \,a^{3}+a^{3} A \right ) \tan \left (f x +e \right )^{5}}{c f}+\frac {i B \,a^{3} x}{c}+\frac {i B \,a^{3} x \tan \left (f x +e \right )^{6}}{c}-\frac {i A \,a^{3}+7 B \,a^{3}}{3 c f}-\frac {2 \left (i B \,a^{3}+5 a^{3} A \right ) \tan \left (f x +e \right )^{3}}{3 c f}-\frac {\left (-2 i A \,a^{3}+6 B \,a^{3}\right ) \tan \left (f x +e \right )^{2}}{c f}-\frac {3 \left (i A \,a^{3}+3 B \,a^{3}\right ) \tan \left (f x +e \right )^{4}}{c f}+\frac {3 i B \,a^{3} x \tan \left (f x +e \right )^{2}}{c}+\frac {3 i B \,a^{3} x \tan \left (f x +e \right )^{4}}{c}}{c^{2} \left (1+\tan \left (f x +e \right )^{2}\right )^{3}}-\frac {a^{3} B \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f \,c^{3}}\) | \(276\) |
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none
Time = 0.25 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.60 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=\frac {{\left (-i \, A - B\right )} a^{3} e^{\left (6 i \, f x + 6 i \, e\right )} + 3 \, B a^{3} e^{\left (4 i \, f x + 4 i \, e\right )} - 6 \, B a^{3} e^{\left (2 i \, f x + 2 i \, e\right )} + 6 \, B a^{3} \log \left (e^{\left (2 i \, f x + 2 i \, e\right )} + 1\right )}{6 \, c^{3} f} \]
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Time = 0.40 (sec) , antiderivative size = 212, normalized size of antiderivative = 1.64 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=\frac {B a^{3} \log {\left (e^{2 i f x} + e^{- 2 i e} \right )}}{c^{3} f} + \begin {cases} \frac {6 B a^{3} c^{6} f^{2} e^{4 i e} e^{4 i f x} - 12 B a^{3} c^{6} f^{2} e^{2 i e} e^{2 i f x} + \left (- 2 i A a^{3} c^{6} f^{2} e^{6 i e} - 2 B a^{3} c^{6} f^{2} e^{6 i e}\right ) e^{6 i f x}}{12 c^{9} f^{3}} & \text {for}\: c^{9} f^{3} \neq 0 \\\frac {x \left (A a^{3} e^{6 i e} - i B a^{3} e^{6 i e} + 2 i B a^{3} e^{4 i e} - 2 i B a^{3} e^{2 i e}\right )}{c^{3}} & \text {otherwise} \end {cases} \]
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Exception generated. \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=\text {Exception raised: RuntimeError} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 242 vs. \(2 (113) = 226\).
Time = 0.87 (sec) , antiderivative size = 242, normalized size of antiderivative = 1.88 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=\frac {\frac {30 \, B a^{3} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}{c^{3}} - \frac {60 \, B a^{3} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + i\right )}{c^{3}} + \frac {30 \, B a^{3} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1\right )}{c^{3}} + \frac {147 \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6} - 60 \, A a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} + 942 i \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 2445 \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} + 200 \, A a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 3620 i \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2445 \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 60 \, A a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 942 i \, B a^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 147 \, B a^{3}}{c^{3} {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + i\right )}^{6}}}{30 \, f} \]
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Time = 8.69 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.09 \[ \int \frac {(a+i a \tan (e+f x))^3 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^3} \, dx=-\frac {a^3\,\left (15\,B\,{\mathrm {tan}\left (e+f\,x\right )}^2-7\,B+B\,\mathrm {tan}\left (e+f\,x\right )\,18{}\mathrm {i}+A\,{\mathrm {tan}\left (e+f\,x\right )}^2\,3{}\mathrm {i}-A\,1{}\mathrm {i}-3\,B\,\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )+B\,\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,\mathrm {tan}\left (e+f\,x\right )\,9{}\mathrm {i}+9\,B\,\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,{\mathrm {tan}\left (e+f\,x\right )}^2-B\,\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,{\mathrm {tan}\left (e+f\,x\right )}^3\,3{}\mathrm {i}\right )}{3\,c^3\,f\,{\left (-1+\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^3} \]
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